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2x-12=5x+3x^2
We move all terms to the left:
2x-12-(5x+3x^2)=0
We get rid of parentheses
-3x^2-5x+2x-12=0
We add all the numbers together, and all the variables
-3x^2-3x-12=0
a = -3; b = -3; c = -12;
Δ = b2-4ac
Δ = -32-4·(-3)·(-12)
Δ = -135
Delta is less than zero, so there is no solution for the equation
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